What's the centrifugal force on an object rounding 170,000 light years circumference in 225 million years?

Answer 1

Convert the numbers to meters and seconds, and evaluate v^2/r. Aside from dealing with really big numbers, the problem is simple.

Answer 2

NOTHING, since "centrifugal force" is a fiction only employable for limited purposes in restricted situations.

In any case, without a specification of mass for the orbiting object (and I presume you must implicitly be thinking of the Sun and therefore ITS MASS), all you can talk about are ACCELERATIONS, and NOT "FORCES," real or fictitious.

On the other hand, the CENTRIPETAL ACCELERATION in such a circular motion --- or indeed in ANY MOTION --- is simply due to forces from the sum of all the material attracting the Sun. To a certain approximation (which can be tuned up if one knows the distribution of matter in the Galaxy), that centripetal acceleration can be thought of as involving all the matter enclosed by the Sun's orbit around the Galaxy. However, it was by examining the velocities of stars and gas clouds orbiting further and further out in our own and other galaxies, that the necessity for positing the existence of dark matter was reasonably firmly established.

Answer 3

44 g

Answer 4

due to the distance and time involved in the trip, the centrifugal force would be negligible

Answer 5

Back-of-envelope order-of-magnitude calculation gives the acceleration as roughly two hundred-billionths of a g. We won't fall off.