2006-12-03 17:18:04 · 6 answers · asked by mary ayola l 1 in Science & Mathematics ➔ Chemistry
in KMnO4 k is +1, Mn is +7 and O is -2
2006-12-03 17:43:37 · answer #1 · answered by ishan m 1 · 1⤊ 0⤋
Jena 1 is correct.
The valency of potassium permanganate KMnO4, or any compound for that matter, is ZERO.
The oxidation state (o.s.) of potassium ion = +1
of manganese = +7
of oxygen = -2
Hence [+1] + [+7] + [4 * (-2)] = 0
2006-12-04 01:33:01 · answer #2 · answered by pete 2 · 1⤊ 0⤋
The valency of potassium permanganate ( KMnO4 ) is 7 (seven)
2006-12-03 17:37:02 · answer #3 · answered by martox45 7 · 1⤊ 0⤋
The valence of any stable compound is 0. In computing for Normality, you could count the number of replaceable hydrogen or hydroxyl ions, and that would be the valence. e.g. the valence of H2SO4 is 2 because it is the number of replaceable hydrogen ions.
2006-12-03 19:00:27 · answer #4 · answered by ? 7 · 1⤊ 1⤋
KMnO4 when it dissociates is K+ and MnO4-
2006-12-03 17:23:01 · answer #5 · answered by borscht 6 · 1⤊ 1⤋
http://www.youtube.com/watch?v=IUOylIeiXFk
2013-11-23 18:42:40 · answer #6 · answered by Anonymous · 1⤊ 0⤋