of 24.0 m/s as it passes over the top of a hill whose radius of curvature is 125m. The mass of the motorcycle and driver is 350 kg. Find the magnitude of the normal force that acts on the motorcycle.
What are the equations that one would use to solve this?
2006-12-03 16:21:04 · 5 answers · asked by larkinfan11 3 in Science & Mathematics ➔ Physics
I think we first need to figure out the centripetal force acting on this guy.
then
F = (m * v^2 )/ r
m=mass, v=velocity, r=radius of curvature
so F = ( 350 * 24*24) / 125
F = 1612.8 Newtons of centripetal force.
the usual term for normal force is usually just reaction of the ground to an object. it's given by
F(normal) = mass * acceleration due to gravity
so here the ground's reaction to the biker (whether he's moving or not) would be
F(normal) = 350 * 9.81 = 3433.5 Newtons
now this force ought to be acting opposite to the centripetal force. I can't say the directions at this point. So, net force would be:
3433.5 - 1612.8 = 1820.7 Newtons
please note here that you haven't given any friction between the bike and the ground, and that may also have some role to play here.
or maybe this is it... the normal force would be that-much if the bike was still. but by moving along a circle, a centripetal force got developed which reduced the net normal force acting on the bike.
check out these articles on wikipedia
http://en.wikipedia.org/wiki/Normal_force
http://en.wikipedia.org/wiki/Centripetal_force
2006-12-03 16:40:42 · answer #1 · answered by answerQuest 2 · 0⤊ 0⤋
The normal force is still 350*9.80662 = 3,432 N That's why any vehicle with sufficient speed will leave the ground as it crests a hill. Only 350(24^2)/125 = 1,613 N is required to hold the bike on the ground at this speed and curvature, so it will FEEL like a force of 1,819 N lifting bike & rider.
2006-12-04 00:51:06 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
The formula to use is m ( g - v^2/r )
= 350 ( 9.8 - 4.608)
= 1817.2 N.
For any object to move along a circle there must be a centripetal force m v v /r.
350 x 24 x 24 / 125 = 1612.8 N.
The weight or the force with which earth pulls him is 350 x 9.8 = 3430 N.
In this 3430 N force 1612.8 N is utilized to keep the body in circular motion.
The remaining force which is pressing the earth is 1817.2 N.
The reaction force is opposite and equal to this force and is 1817.2 N.upward.
2006-12-04 01:03:30 · answer #3 · answered by Pearlsawme 7 · 0⤊ 0⤋
The magnitude will be the mass of the motorcycle plus the driver minus the centripetal force needed to pass the curve hill.
Try to use the formula for centripetal force: F = (m v^2)/r
2006-12-04 00:33:33 · answer #4 · answered by Paw 3 · 0⤊ 1⤋
The normal force will be the motorcycle's weight minus the centripetal force required for it to travel on the curve of the hill.
Centripetal force is F = (m v^2)/r
2006-12-04 00:25:41 · answer #5 · answered by Robert A 2 · 1⤊ 0⤋