Heres what I have to do:
Write the equation of the line that passes through point (-3,-5) and (3,0).
First I found the slope:
m = [0 - (-5)] / [3 - (-3)] = 5/6
I'm having trouble finding the y-intercept from the coordinates given. Help is much appreciated! Thanks in advance : )
2006-12-03
15:28:41
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9 answers
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asked by
glitteringfairywings
2
in
Science & Mathematics
➔ Mathematics
Ah, ok.. so I just had to plug in one of the set of coordinates. Alrighty, thanks all! : )
2006-12-03
15:37:56 ·
update #1
Ok, given the points (-3,-5) and (3,0)
The slope is correct, rewriting
m=(0-(-5))/(3-(-3))=5/6
so we have y=(5/6)x +b , and we need to find b. b is the y-intercept.
Put either point in the equation and solve for b, both of them must work!
(3,0) : 0=(5/6)(3)+b , b=-5/2
(-3,-5): -5=(5/6)(-3)+b , -5=(-5/2) +b, again b=-5/2
Hope this helps!
2006-12-03 15:39:28
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answer #1
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answered by William M 2
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To find the y-intercept, use the formula:
y = mx + b
b = y - mx
So choose one of the 2 points given and plug their values into the equation. So using (3,0):
b = 0 - 5/6(3)
b = -5/2
So from here, it's easy to figure out the equation of the line. If you need further help, it is
y = 5/6x - 5/2
if your teacher doesn't like fractions, you can simplify by multiplying both sides by 6 to get
6y = 5x - 15
2006-12-03 23:37:50
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answer #2
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answered by euclidjr 2
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Write
y=mx+b
you know m and you can use either point in the equation to get b:
0=m*3+b
b=-3m=-3(5/6)=-5/2
therefore,
y=5x/6 -5/2
It's good to check the answer
for point 1
-5 =? 5(-3)/6-5/2 = -15/6-15/6 = -30/6 = -5 OK, it checks.
2006-12-03 23:31:45
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answer #3
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answered by modulo_function 7
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Here's the next step:
(y-y1)=m(x-x1)
y-(-5)=5/6(x-(-3))
y+5=5/6(x+3)
y+5=5/6x+15/6
y=5/6x+5/2-10/2
y=5/6x-5/2
2006-12-04 10:17:41
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answer #4
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answered by Anonymous
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Since you have the slope use the slope intercept form:
y=mx+b
Plug in 5/6 as the slope, then plug in one of the points and solve for b.
Then put the pieces together and get your equation.
2006-12-03 23:31:54
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answer #5
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answered by AibohphobiA 4
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y = mx + c
take one of the given values of (x,y). we take (3,0)
then, c = y - mx = 0 - 5/6*3 = - 5/2
y-intercept = - 5/2
2006-12-03 23:32:28
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answer #6
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answered by placebo 2
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y = mx + b
Substitute, using your calculated m, and solve for b:
-5 = (5/6) (-3) + b
-5= -15/6 + b
-2.5= b
or
0= 5/6 (3) + b
0= 15/6 + b
-2.5 = b
so it checks out.
Done.
2006-12-03 23:34:43
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answer #7
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answered by Jerry P 6
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This is the formula to write the equation for the above points :
y - y1 / x - x1 = y2 - y1 / x2 - x1
2006-12-03 23:43:21
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answer #8
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answered by bhavishyathi 3
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m=(-5-0)/(-3-3)=-5/(-6)=5/6
y=5x/6+b
0=5*3/6+b
-5/2=b
b=-5/2
y=5x/6-5/2
check
-5=5(-3)/6-5/2
-5=-5/2-5/2=-10/2=-5
2006-12-03 23:33:05
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answer #9
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answered by yupchagee 7
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