A)2 3 15
B)3 3 11
C)2 3 13
D)3 3 13
2006-12-03 14:58:05 · 5 answers · asked by Hairdresser4you 3 in Science & Mathematics ➔ Mathematics
Come on, on multiple choice, only one of those answers even multiplies together to equal 117 - you can find it.
For what it is worth, there is a rule that any number is divisible by 3 if the sum of its digits can be divided evenly by 3. Since the numbers in 117 add to 9 (1 + 1 + 7 = 9) and 9 is divisible by 3, that means 3 is a factor of 117. You can continue from there. Good luck!
2006-12-03 15:05:28 · answer #1 · answered by Pi R Squared 7 · 0⤊ 0⤋
117=3^2*13
D) 3*3*13
2006-12-03 23:15:16 · answer #2 · answered by yupchagee 7 · 0⤊ 0⤋
A will not work since 15 is NOT prime.
B will not work because 9x11=99.
C will not work because 6x13=78.
D works because all are prime factors and their product is 117! Have a great holiday!!
Eds
2006-12-03 23:18:11 · answer #3 · answered by Eds 7 · 0⤊ 0⤋
Simple, just multiply each factorization and see if they result to 117.
2006-12-03 23:01:14 · answer #4 · answered by AibohphobiA 4 · 0⤊ 0⤋
D
2006-12-03 23:03:37 · answer #5 · answered by emma 6 · 0⤊ 0⤋