2x² + 5x = 12
2006-12-03 14:52:54 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Solution:
2x² + 5x - 12 = 0
(2x - 3) (x + 4) = 0
Solve for x:
2x - 3 = 0
x = 3/2
and
x + 4 = 0
x = -4
2006-12-03 14:59:16 · answer #1 · answered by euclidjr 2 · 0⤊ 0⤋
Set the equation equal to zero
2x^2+5x-12
Factor
(2x-3)(x+4)
Set each equal to zero separately and solve. You'll have 2 answers.
2x=3
x=3/2
and
x=-4
2006-12-03 14:59:17 · answer #2 · answered by Pius Thicknesse 4 · 0⤊ 0⤋
2x^2+5x=12
or,2x^2+5x-12=0
(-5+-Sqr(25-4*2*(-12))/)2*2
=(-5+-Sqr25-72/)4
=(-5+-Sqr47)/4 Solved
2006-12-03 15:01:30 · answer #3 · answered by aminnyus 2 · 0⤊ 0⤋
2x² + 5x = 12
2x^2+5x-12=0
(2x-3)(x+4)
2x-3=0
x=3/2
x+4=0
x=-4
roots are
x=3/2, -4
2006-12-03 15:16:55 · answer #4 · answered by yupchagee 7 · 0⤊ 0⤋
2x^2 + 5x = 12
2x^2 + 5x - 12 = 0
x = (-b ± sqrt(b^2 - 4ac))/(2a)
x = (-5 ± sqrt(5^2 - 4(2)(-12)))/(2(2))
x = (-5 ± sqrt(25 + 96))/4
x = (-5 ± sqrt(121))/4
x = (-5 ± 11)/4
x = (-16/4) or (6/4)
x = -4 or (3/2)
ANS : x = -4 or (3/2)
2006-12-03 15:06:58 · answer #5 · answered by Sherman81 6 · 0⤊ 0⤋
Subtract the 12 from both sides, then with the resulting quadratic solve for x by using either factoring or quadratic formula.
2006-12-03 14:56:36 · answer #6 · answered by AibohphobiA 4 · 0⤊ 0⤋
With x solved it will look like this: 3+1.5+7.5=12
x=1.5
2006-12-03 22:38:36 · answer #7 · answered by Anonymous · 0⤊ 0⤋
i dont understand why none of these problems are working out fo me tonight...???
2006-12-03 14:57:49 · answer #8 · answered by ? 3 · 0⤊ 0⤋