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I need help on this problem:

Find the horizontal range of a baseball that leaves the bat at an angle of 63 degrees with the horizontal with an initial velocity of 160 km/h. Disregard air resisitance.

2006-12-03 14:36:59 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

conversion 160km/h = 44.4 m/s

Horizontal component = 44.4 * cos 63 = 20.2 m/s
Vertical component = 44.4 * sin 63 = 36.6 m/s

Total time in air = 2 * (36.6 - 0) / 9.81 = 7.46 s

Range = 20.2 * 7.46 = 151m

2006-12-03 14:41:17 · answer #1 · answered by Math-Chem-Physics Teacher 3 · 0 0

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