math help?

Question

i dont understand these 3 problems at all


writ an equation of the line that has each pair of intercepts

x-intercept:1, y-intercept:-4


x-intercept:-1, y-intercept:3


x-intercept:3, y-intercept:-3

Answer 1

Alright here we go.

Just make a y=mx+b expression. Remember, b = y-intercept and m=slope. Slope is the difference in the y's divided by the difference in the x's between 2 coordinates or in other words, "rise over run."

The first one is y=4x-4. Your two pts are 1,0 (x intercept) and 0,-4 (y intercept) so the difference in the y's is 4 (0 - -4=4) amd your difference in the x's in 1 (1-0 = 1). 4 divided by 1 is 4 so there u go.

Here are the other coordinates so you can do them
-1,0; 0,3
3,0; 0,-3

Answer 2

With an intercept, you are given a point. For example, the first one:

x-intercept:1, y-intercept:-4

gives you the points (1,0) and (0,-4). As two points are required to define a line, you can then use these to create an equation for the line.

Answer 3

This is ONE line that has these three traits? I don't see how a line would exist with 3 different x and 3 different y-intercepts.

Answer 4

x-intercept:1, y-intercept:-4
y=4x-4

x-intercept:-1, y-intercept:3
y=3x+3

x-intercept:3, y-intercept:-3
y=-x-3