..........π
f(x)=∫(1+cost)dt , f'(x)= ?
..........x
2006-12-03 13:46:38 · 6 answers · asked by wafflehouse 4 in Science & Mathematics ➔ Mathematics
What I am trying to find is the derivative of the integral of (1+cost) from π to x.
2006-12-03 13:53:17 · update #1
taking the derivative (f ' (x) ) gets rid of the whole integral, because they are opposites. Just like sqrt is the opposive of something squared.
So, you'd just get:
1 + cost
replace the t with an x as called for in the f ' (x)
so, you'd just get
f ' (x) = 1 + cos(x)
simple, eh? :)
2006-12-03 13:55:46 · answer #1 · answered by antheia 4 · 1⤊ 0⤋
Use the fundamental theorem of calculus. Hint: the answer rhymes with f'(x)= -(1+cos(x)).
2006-12-03 21:52:45 · answer #2 · answered by csferrie 2 · 1⤊ 0⤋
if your trying to find the dervative of (1+cost) it would be -sin, I think?
2006-12-03 21:50:05 · answer #3 · answered by Oli V 2 · 0⤊ 0⤋
use the program "Derive"
i think its free its easy to use and intuitive
2006-12-03 21:56:02 · answer #4 · answered by Heat 3 · 0⤊ 0⤋
when integrated you get t + sint from pi -> x
pi + sin pi = pi -(x + sin x)
= pi - x + sinx
2006-12-03 21:50:34 · answer #5 · answered by Modus Operandi 6 · 0⤊ 0⤋
Here's my teacher's site... you can ask her! ...
alice.pollock@nhmccd.edu
2006-12-03 21:56:38 · answer #6 · answered by Diva 1987-2007 1 · 0⤊ 0⤋