2006-12-03 13:40:22 · 7 answers · asked by Red 1 in Science & Mathematics ➔ Mathematics
For an integer to be divisible by 4 its last 2
digits must be divisible by 4. Since 20,24 and 28
are divisible by 4, the answers are 0, 4 and 8.
2006-12-03 14:11:46 · answer #1 · answered by steiner1745 7 · 2⤊ 0⤋
The ? could be 0, 4, or 8.
A number is divisible by 4 if the last two digits are divisible by four. 20, 24, and 28 are all divisible by four.
2006-12-03 22:17:20 · answer #2 · answered by danielomm314 2 · 1⤊ 0⤋
0 4 or 8
2006-12-03 21:45:46 · answer #3 · answered by Mayur 2 · 0⤊ 0⤋
The ? mark can be replaced by a 0, 4, or 8, and the answer will still be divisible by 4
2006-12-03 21:43:52 · answer #4 · answered by pstategirl 2 · 3⤊ 1⤋
824 or 828 are divisible by 4
2006-12-03 21:42:17 · answer #5 · answered by Modus Operandi 6 · 2⤊ 0⤋
824
If the number formed by the last two digits of the number is divisible by 4, then the original number is divisible by 4.
828 is also a correct answer.
2006-12-03 21:42:37 · answer #6 · answered by MsMath 7 · 1⤊ 2⤋
20*41 = 820
19*42 = 798
19*43 = 817
19*44 = 836
19*45 = 855
18*46 = 828
18*47 = 846
17*48 = 816
17*49 = 833
no digit works
2006-12-03 22:28:26 · answer #7 · answered by mayi o 4 · 0⤊ 1⤋