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1.) ln cubert3(sqrt 3r^2s))

2006-12-03 13:23:44 · 1 answers · asked by Anonymous in Science & Mathematics Mathematics

1 answers

are you asking

ln(cbrt(sqrt(3r^2s))) =
ln((3r^2s)^(1/2))^(1/3) =
ln((3r^2s)^(1/6)) =
(1/6)ln(3r^2s) =
(1/6)(ln(3) + ln(r^2) + ln(s)) =
(1/6)(ln(3) + 2ln(r) + ln(s))

2006-12-03 14:20:03 · answer #1 · answered by Sherman81 6 · 0 0

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