algebra fractions?

Question

I need to figure out how to do algebra problems using fractions:

x - 1/3 = -25/3

Answer 1

well...

you have two choices. One, just treat the fractions like normal numbers:

x - 1/3 = -25/3
x - 1/3 (+ 1/3) = -25/3 (+ 1/3)
x = -24/3
x = -8

or, you could get rid of the fractions by multiplying by the LCD, in this case, 3:

(x - 1/3) * 3 = (-25/3) * 3
3x - 1 = -25
3x - 1 + 1 = -25 + 1
3x = -24
3x/3 = -24/3
x = -8

Hope this helps :)

Answer 2

FIRST the reason; i will substitute - 3 / 5 for x in the unique equation and notice if the two sides of the = are certainly equivalent -3/5/ (-3/5 + a million) = ( 3/ (2 x -3/5)) + a million -3/5/2/5 = ( 3/ - 6/5) + a million -3/2 = ( 15/ -6) + a million -5/2 = ( -15/ 6) DIVIDE by employing 3/3 = -5/2 the respond is stable AND -5/2 = - 2.5 suggestion; in case you have fraction difficulty, use a calculator that provides decimal effects to transform all fractions to decimal . Sorry I had no room to describe all yet between the regulations/steps

Answer 3

x = -25/3 + 1/3
= -24/3

Answer 4

x - 1/3 = -25/3

You wnat to first clear the denominators of the fractions by multiplying both sides of the equation by their LCD. Here the denominators are the same, so multiply by 3.

3(x - 1/3) = - 3(25/3)
3x - 1 = - 25

And the rest you have done before

Answer 5

to add fractions with the same denominator just add their numerators. (e.g. 5/4 + 2/4 = 7/4).

If their denominators are different mutiply one fraction numerator and denominator by the other one. E.G.:

3/5 + 4/7 =
(3/5)7 + (4/7)5 =
21/35 + 20/35=
41/35

The answer to your problem should be x = 24/3.

Answer 6

get rid of the fractions if you can.
3(x-1/3=-25/3)
3x-1=-25
3x= -24
x= -8

Answer 7

x = -8