What is the minimum work needed to push a 900 kg car 420 m up a 17.5° incline with zero friction?

Question

That's the whole question.

I would appreciate it if someone could help me with this question as soon as possible.

Answer 1

Trigonometry says the car gains 420*sin(17.5) m in elevation. Call that value h.

Work done = potential energy gained = m*g*h

Answer 2

not to sure about this but i'll try it
W=(F cosθ)d
F= mg
W=(900kg)(9.8m/s)(cos 17.5)420m
W=3532949j
seems like a lot of work but hey I tried.