Use the Laws of Logarithms to combine the expression.?

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log5(x^2-1) - log5(x-1)

2006-12-03 12:44:55 · 4 answers · asked by jere 1 in Science & Mathematics ➔ Mathematics

log5(x^2-1) - log5(x-1)
= log5 [(x^2-1)/(x-1)]
= log5 [(x-1)(x+1)/(x-1)]
= log5 (x+1)

2006-12-03 12:53:11 · answer #1 · answered by buaya123 3 · 0⤊ 0⤋

log5(x^2-1) - log5(x-1)
log5 [(x^2-1)/(x-1)]
log5 [(x+1)(x-1)/(x-1)]
log5 [(x+1)]
only works when x is not 1.

2006-12-03 20:53:26 · answer #2 · answered by Nick C 4 · 0⤊ 0⤋

log5(x^2-1) - log5(x-1)

log5(x^2-1)/(x-1)
log5(x-1)(x+1)/(x-1)
log5(x+1)

2006-12-03 20:53:13 · answer #3 · answered by Anonymous · 0⤊ 0⤋

log(5)(x^2 - 1) - log(5)(x - 1)
log(5)((x^2 - 1)/(x - 1))
log(5)(((x - 1)(x + 1))/(x - 1))
log(5)(x + 1)

2006-12-03 22:32:53 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋