2006-12-03 12:39:11 · 3 answers · asked by celticevening 1 in Science & Mathematics ➔ Mathematics
To determine the celsius value, C=5/9(F-32)
2006-12-03 13:02:01 · answer #1 · answered by kamaole3 7 · 0⤊ 0⤋
Here are some hints:
You can take any equation and subtract the same thing from both sides and the equation will still be valid.
First, Subtract the same thing from both sides, so that "9/5C" is the only term on the right.
Second, note that you can multiply both sides of an equation by any number and the equation will still be valid. So, once you have
"something" = 9/5C
then multiply both sides by the same number (hint - it's a fraction) so that
"something else" = C
Then you're done!
2006-12-03 20:47:18 · answer #2 · answered by firefly 6 · 1⤊ 0⤋
F=9/5C+32
F-32=9/5C -- subtract both sides by 32
F-32 over 9/5=C divide both sides by 9/5
2006-12-03 20:47:45 · answer #3 · answered by immageek 1 · 0⤊ 1⤋