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log2(xy)^10

2006-12-03 12:35:58 · 3 answers · asked by im_all_about_spades2003 1 in Science & Mathematics Mathematics

3 answers

10log2x + 10 log2y

2006-12-03 12:38:06 · answer #1 · answered by Dennis T 1 · 0 0

1. You have 2 terms in the log: 2 and (xy)^10
by the rule, you can separate these into addition of logs:

log 2 + log(xy)^10


2. Exponents for the term in log can be brought to the front to multiply

log 2 + 10log(xy)


3. similar to the first rule, we can separate out the x and y into addition of logs(don't forget the 10!)

log 2 + 10logx + 10logy

And there's your answer.

Another way:

1. Since the x and y in the parenthesis are being multiplied instead of added, they each carry the 10 exponent, so you can get rid of the parenthesis

log 2 * x^10 * y^10


2. Now you're ready for the Law. Separating the multiplied terms into addition of logs

log 2 + log x^10 + log y^10


3. Now you're ready for the exponent rule. In each log term with an exponent, you can bring the exponent to the front to be multiplied

log 2 + 10log x + 10log y

2006-12-03 20:47:15 · answer #2 · answered by antheia 4 · 0 0

log(2)(xy)^10
10(log(2)(xy))
10(log(2)x + log(2)y)

2006-12-03 22:38:00 · answer #3 · answered by Sherman81 6 · 0 0

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