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Simplify the complex fraction. Remember to include any changes in the domain.

2006-12-03 12:26:03 · 6 answers · asked by Nischal P 1 in Science & Mathematics Mathematics

6 answers

3/(x+1) = 3/(x+1)
1/x/(2/(x+1) = (x+1)/2x = 1/2+ 1/2x
3/x = 3/x

add then 3/(x+1) + 1/2+1/2x+3/x
= 1/2+ 3/(x+1) + 7/2x
= 1/2+(6x+7x+7)/(2x(x+1)
= 1/2+ (13x+7)/(2x(x+1))

2006-12-03 12:35:47 · answer #1 · answered by Mein Hoon Na 7 · 0 0

(1/x)/(2/(x+1)) = (1/x) * (x+1)/2 = (x+1)/2x

Common denominator of the three factors is 2x(x+1)

6x/(2x(x+1)) + (x+1)(x+1)/2x(x+1) + 6(x+1)/2x(x+1) =
(6x + x^2 +2x +1 +6x +6)/2x(x+1) =
(x^2 +14x + 7) / 2x(x+1)

Domain is all x where x is not 0 or -1

2006-12-03 20:36:20 · answer #2 · answered by Steve A 7 · 0 0

hi

2006-12-03 20:33:33 · answer #3 · answered by CrippledFingerz 3 · 0 0

if we will solve it this way (3)(x+1)= (3)(1x)+ 3x plus (1x)2x)+(3x)=11x.
or
we can say (3)X(1x)=3x +(1xX2X1x)+2x2 +3x=
3x+2x2+3x=0


am got confused cant think any more i know i can find an answer for this one but i stoped studieng math aloooong time ago please tryto send me the answer at deeb_hurted@yahoo.com i will be so happy to know the answer.

2006-12-03 20:47:29 · answer #4 · answered by lola batoot 2 · 0 0

((3/(x + 1)) + (1/x)) / ((2/(x + 1)) + (3/x))
((3x + (x + 1))/(x(x + 1))) / ((2x + 3(x + 1))/(x(x + 1)))
((3x + x + 1)/(x(x + 1))) / ((2x + 3x + 3)/(x(x + 1)))
((4x + 1)/(x(x + 1))) / ((5x + 3)/(x(x + 1)))
((4x + 1)/(x(x + 1))) * ((x(x + 1))/(5x + 3))
(x(4x + 1)(x + 1))/(x(5x + 3)(x + 1))
(4x + 1)/(5x + 3)

2006-12-03 20:49:30 · answer #5 · answered by Sherman81 6 · 0 0

that sh!t is bananas.
i'm not doing your homework for you sorry.

2006-12-03 20:28:13 · answer #6 · answered by sugarbabealison 2 · 0 2

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