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On an SAT math section. There was a question like this:
If the sum of all lengths of a cube is 8 what is the volume of the cube?
so I drew the cube and there was 4 lengths so I divided
8/4=2 therefore the length=2 and the width=2 and height=2 since Volume of a cube is =lwh.
My answer was 8. was i correct?

2006-12-03 12:02:03 · 5 answers · asked by avalentin911 2 in Science & Mathematics Mathematics

the sum of all the length without width and height. There were 5 answers and they were all integer answers.

2006-12-03 12:08:47 · update #1

the answer choices were like
a.2
b.4
c. 6
d. 8
e. 10

2006-12-03 12:15:34 · update #2

5 answers

The sum of all lengths of a cube doesn't make sense- did it say the lengths of the EDGES of a cube?

If so, a cube has 12 edges; 8/12 = 2/3 = length of any one edge, and Volume = (2/3)^3 = 8/27

2006-12-03 12:04:58 · answer #1 · answered by hayharbr 7 · 0 0

Your answer was incorrect, unfortunately.

if l + w + h = 8

And we know that l = w = h (because it's a cube).

Then l = w = h = 8/3

Therefore, the volume of the cube is (8/3)^3 = 512/27

2006-12-03 12:08:25 · answer #2 · answered by sep_n 3 · 0 0

nope ur wrong
8= l+W+h right?
then L=w=h ok?
then u divide 8 by 3
8/3 = 2u 1/3= l=w=h
so each side is 2u 1/3
then times it together (2 u 1/3)^3

8/3 times 8/3 = 64/9
64/9 times 8/3 is 512/27

then simp> = 18u 26/27

plz when u get it back the scores plz tell me r scores
i took the nov 4 one and got 1410

2006-12-03 12:19:08 · answer #3 · answered by azn boy 2 · 0 0

in case you enable the size of the edge of the cube be a, then the cube's quantity is a^3. the quantity of the cylinder is base section x top = pi a^2 a = pi a^3 (the radius is a, and the top is likewise a) The ratio of the cube quantity to the cylinder quantity is then a^3 / (pi a^3) = one million/pi (A)

2016-12-29 20:41:44 · answer #4 · answered by bolander 3 · 0 0

You drew a square.

LOL!

Based on your inability to repeat the question, it is not clear which of the first two answers is correct. They are both correct, based on their "best guess" for what the question really meant.

2006-12-03 12:11:50 · answer #5 · answered by Anonymous · 0 0

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