4, 5, 6, 9, 11
33, 72, 23, 27, 77, 68, 85
2006-12-03 11:53:41 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
In an odd set of numbers, to find the median, we just arrange them in order, and then take the one in the middle.
The median of 4, 5, 6, 9, 11 is 6.
To find the median of the second set, first sort it. We get 23, 27, 33, 68, 72, 77, 85. The median is 68.
2006-12-03 11:56:16 · answer #1 · answered by Anonymous · 0⤊ 0⤋
The first ones already in order, so just take the middle number - 6.
Arrange the second list in order:
23 27 33 68 72 77 85
The middle number is 68.
2006-12-03 11:56:06 · answer #2 · answered by stephen m 4 · 0⤊ 0⤋
The median of a finite record of numbers could nicely be chanced on via arranging all the observations from lowest value to maximum value and selecting the middle one. If there are a good style of observations, one many times takes the advise of the two center values. in the occasion there are a good quantity.. So the MEDIAN is the advise (wide-spread) of 26 and 30.. 30 +26=fifty six fifty six/2 = 28
2016-12-29 20:41:36 · answer #3 · answered by bolander 3 · 0⤊ 0⤋
6 , 68
2006-12-03 11:59:20 · answer #4 · answered by bainter4 1 · 0⤊ 0⤋
Median = "middle" number when the numbers are put in order, so
First set is "6"
Second set is "68"
2006-12-03 11:55:38 · answer #5 · answered by sep_n 3 · 0⤊ 0⤋
The median is the middle value of the list. For the first series it's 6......you figure out the second one on your own.
2006-12-03 11:55:39 · answer #6 · answered by Inquisitor-2006 5 · 0⤊ 0⤋
6
68
2006-12-03 13:25:56 · answer #7 · answered by Anonymous · 0⤊ 0⤋
first one is 6
second one is 68
2006-12-03 11:55:59 · answer #8 · answered by Tanvi gurl 3 · 0⤊ 0⤋