Angle GHI, g=32, h=52, 1=27. Find the measure of the largest angle in the most efficient manner. Explain why your process is efficient.
2006-12-03 11:17:44 · 4 answers · asked by shitheadjulie1 1 in Science & Mathematics ➔ Mathematics
I assume you mean that GHI is a triangle with sides 32, 52, and 17.
By the Law of Sines, the largest angle will be the angle opposite the side of length 52. We can find this using the Law of Cosines:
a^2 = b^2 + c^2 - 2bc cos A
Plugging in to find the angle opposite the side of length 52, we get
52^2 = 32^2 + 27^2 - 2 * 32 * 27 cos A
2704 = 1024 + 729 - 1728 cos A
951 = -1728 cos A
cos A = -951/1728
A = inverse cosine of -951/1728
So A = about 2.15 radians, or about 123 degrees.
2006-12-03 11:30:01 · answer #1 · answered by Anonymous · 0⤊ 0⤋
5/9= 40 5/80 one 7/10= sixty 3/ninety 5= 25/25 3/50= 18/3 hundred 7/8= 28/32 9= 36/4 11/18= 33/fifty 4 7/12= fifty six/ninety six 5/thirteen= sixty 5/169 9/25= 36/1000 Now listed under are another problemos: Writing a fraction in easiest type: 2/14 one million/7 12/8 3/2 14/35 2/5 20/40 4 10/11 12/6 2/one million 40 4/60 11/15 a hundred and forty/297 Lowest words already 33/a hundred and ten 3/10 80/40 5 sixteen/9
2016-12-29 20:40:42 · answer #2 · answered by bolander 3 · 0⤊ 0⤋
The largest angle opposes the longest side.
2006-12-03 11:24:31 · answer #3 · answered by modulo_function 7 · 0⤊ 0⤋
The largest angle is opposite the longest side.
Use law of cosines, law of sines.
2006-12-03 11:21:54 · answer #4 · answered by davidosterberg1 6 · 0⤊ 0⤋