I will only pick a best answer out of those submitted BEFORE kickoff, so answer fast!
2006-12-03 11:09:17 · 12 answers · asked by But why is the rum always gone? 6 in Sports ➔ Football (American)
Hawks (another Seattle-ite here) 'cause they'll blitz the heck out of the rook.
Hopefully, they'll be able to tackle someone.
2006-12-03 11:14:12 · answer #1 · answered by cantthinkofanygoodnames 3 · 2⤊ 1⤋
Well I'm also a Big Broncos fan. I think it was a mistake putting plummer on the bench this late in the season. He has not played any different then he has from the first game. I would say Seattle wins it but it will be a good game.
2006-12-03 19:24:30 · answer #2 · answered by ? 4 · 1⤊ 0⤋
Seatle...35-24 over the Broncos
2006-12-03 19:13:26 · answer #3 · answered by nas88car300 7 · 1⤊ 0⤋
I would go with Seattle. We haven't seen Jay Cutler in a NFL start yet and is playing against a decent Seattle team. Seattle also has all their offensive weapons back on the field (Hasselbeck and Alexander) from injuries. I think it will be a close game though as Denver is going to rely on the defense to stop the 'Hawks.
My prediction?
Seattle 17
Denver 13
2006-12-03 19:23:28 · answer #4 · answered by ~LT_21~ 3 · 1⤊ 0⤋
Broncos
2006-12-03 19:10:35 · answer #5 · answered by imakegirlzgoloco 2 · 0⤊ 1⤋
I want Broncos, but think Seahawks will win. The Broncos have not had it together lately.
2006-12-03 19:14:55 · answer #6 · answered by Me 3 · 1⤊ 0⤋
Broncos because Jay Cutler is starting at QB.
2006-12-03 19:15:01 · answer #7 · answered by miky2tones 2 · 0⤊ 1⤋
I say the Seahawks, and the reason why is because I want the Bronco's to lose. It helps out my Bengals team. hehe.....
2006-12-03 19:10:49 · answer #8 · answered by Jen 5 · 0⤊ 1⤋
I am a HUGE bronco fan and know that Plummber is not playing i think the broncos will have a chance at winning!!!!
2006-12-03 19:19:58 · answer #9 · answered by horse_lover_mv 2 · 0⤊ 1⤋
Seahawks you got alexander and hassleback against an inexperienced cutler
2006-12-03 19:14:10 · answer #10 · answered by Markymark 2 · 1⤊ 0⤋