I need P2...
P1=850 mmhg
V1=1.5 L
T1=288*K
V2=2.5 L
T2=303*K
Please help quick... will give 10 points to correct answer!!!
2006-12-03 10:40:49 · 4 answers · asked by B-Rad 4 in Science & Mathematics ➔ Chemistry
Not trying to cheat, need serious help, please give formula and entire equation. Thanks everyone.
2006-12-03 10:57:36 · update #1
I hope I'm not doing your homework...
Recall: (P1*V1)/T1 = (P2*V2)/T2
Therefore: (850 mm Hg)(1.5L)/(288 K) = (P2)(2.5L)/(303K)
P2 = 536.6 mm Hg
This is reasonable because you are increasing volume and temperature... thus, pressure goes down.
2006-12-03 10:48:35 · answer #1 · answered by Jin 3 · 0⤊ 0⤋
General Gas Law says P1V1/T1 = P2V2/T2
so plug in the numbers:
850mmhg*1.5 L/288K = P*2.5 L/303K
P= 536mmhg
to 2 sig figs: 540 mmhg
2006-12-03 19:30:43 · answer #2 · answered by sponges 2 · 0⤊ 0⤋
No offense, but are you serious? How will you learn if you do not try?
Look. Put what you have on one side and what you don't need on the other of PV=nRT.
You need P, V, and T.
PV/T=nR
nR is constant, so you can replace it will your final values.
P1V1/T2 = P2V2/T2
Solve for V1:
V1=P2V2T2/T2P1
I really hope this helps. PRACTICE over and over and you will be excellent at these problems. They are easier than you think..
2006-12-03 18:46:19 · answer #3 · answered by Hadeer S 1 · 0⤊ 0⤋
(p1)(v2) / (t1) = (p2) (v2) / (t2)
first, convert 850mmhg to atm
850mmhg = 1.118atm
now, sub in the variables for numbers!
(1.118atm)(1.5L) / (288K) = (x) (2.5L) (303K)
x = 0.64 atm = 486.399mmhg
2006-12-03 19:30:53 · answer #4 · answered by mennor 2 · 0⤊ 0⤋