Combined Gas Law...
I need T1...
P1=95 kPa
V1=4.0 L
P2=101 kPa
V2=6.0 L
T2=471*C w/kelvin
Will give 10 POINTS to correct answer... please
2006-12-03 10:25:40 · 4 answers · asked by B-Rad 4 in Science & Mathematics ➔ Chemistry
hmm PV = nRT ---> PV/T = nR (since nR is constant, we can neglect)
P1V1/T1 = P2V2/T2 o..k..., after several manipulation u get this : (P1V1T2)/(P2V2)= T1
is ur T2 value = 471 celsius? or Kelvin? hmm.. looks like kelvin..
anyway, (95kPa X 4L X 471Kelvin)/(101kPa X 6L) = 295.34 Kelvin..
now, if ur T2 value is Celsius, the degree mark will be in celsius.. it does not play a role here, because u r merely measuring Ration equivalence, therefore just match the units, if T1 = kelvin, T2 = kelvin.. but if u want a regular value in PV = nRT, then units matter, especially R-constant gas law..
2006-12-03 10:34:11 · answer #1 · answered by J 3 · 0⤊ 0⤋
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2016-11-23 15:04:49 · answer #2 · answered by ? 4 · 0⤊ 0⤋
Use P1V1/T1 = P2V2/T2, and just plug in the numbers and grind it out. You need no more calcuating power than a cheap four-banger.
2006-12-03 10:28:42 · answer #3 · answered by Anonymous · 0⤊ 0⤋
Ummm...look in your other question. We already answered it for you. Instead, rearrange for T1. It shouldn't be too hard.
2006-12-03 10:28:15 · answer #4 · answered by Hadeer S 1 · 0⤊ 0⤋