Combined gas law???
I get all the others, this 1 one confusing to me.
I need to find P1,
V1=750 ml
T1=273*C w/kelvin
P2=2.0atm
V2=500mL
T2=298*C w/Kelvin
2006-12-03 10:18:07 · 3 answers · asked by B-Rad 4 in Science & Mathematics ➔ Chemistry
(PV/nRT)1 = (PV/nRT)2
n and R cancel out
left with (PV/T)1 = (PV/T)2
(P1*0.75L)/273 = (2 *0.5 L)/298
P1 = 1.22 atm
When completing ideal gas problems, keep in mind that all temps need to be in Kelvin, pressures needs to be in atms, and volumes need to be L units.
2006-12-03 10:25:21 · answer #1 · answered by Brett M 2 · 0⤊ 0⤋
(P1*V1)/(T1) = (P2*V2)/(T2)
P1 = (P2*V2*T2)/(V1*T2)
Plug and chug.
Your units can stay as is because you do not need to constant "R" anymore. You will still get your answer in atm.
2006-12-03 18:22:34 · answer #2 · answered by Hadeer S 1 · 0⤊ 0⤋
(P1*V1) / (T1) = (P2*V2) / (T2)
now just solve for P1
2006-12-03 18:22:40 · answer #3 · answered by Matt S 2 · 0⤊ 0⤋