These are easy problems...You have to get x alone to solve for it.
First multiply the 7 out.
7x+49=5x+59
Then subtract the 49 from both sides
7x=5x+10
Then subtract the 5x from both sides
2x=10
Then divide the 2 from both sides to get the X alone
x=5
To check your answer, but 5 in for x in the original problem and answer.
7(5 + 7) = 5(5) + 59
7(12)=25 + 59
84=84
Which means x is 5
2006-12-03 10:09:37
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answer #1
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answered by Jessica 6
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5
2006-12-03 10:03:54
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answer #2
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answered by RetroBunny69 5
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Fairly simple
First do the multiplication like this
7x+49=5x+59
Now Subtract 5x from both sides of the equasion like this
7x+49-5x=5x+59-5x
This gives you
2x+49=(5x-5x)+59
More specifically
2x+49=59
Now subtract 49 from both sides of the equasion
2x+49-49=59-49
More specifically
2x=10
Now multply both sides of the equasion by 1/2 so you figure for x
1/2*2x=1/2*10
x=5
Prove your answer by replacing 5 for the x value in the original equasion
7(5+7)=5(5)+59
Rules do insides of parentices first
7(12)=5(5)+59
84=25+59
84=84
2006-12-03 10:16:37
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answer #3
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answered by Gary M 3
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x = 5
2006-12-03 10:04:21
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answer #4
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answered by Anonymous
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7(x+7)=5x+59 distribute 7
7x+49=5x+59 subtract 5x from each side
2x+49=59 subtract 49 from each side
2x=10 divide by 2
x=5
2006-12-03 10:04:45
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answer #5
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answered by yupchagee 7
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7(x+7)=5x+59
7x+49=5x+59
7x-5x=59-49
2x=10
x=5
so x=5
2006-12-04 04:11:26
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answer #6
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answered by Hemali 2
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7x - 2 (x - 2) + 5 (x + 3) = 7x - 2x + 4 + 5x + 15 strengthen what's contained in the bracket and write it out = 7x - 2x + 5x + 4 + 15 crew each of the x-es and numbers jointly = 10x + 19 subtract/upload the x-es and the numbers
2016-11-23 15:02:29
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answer #7
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answered by ? 4
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7x + 49 = 5x + 59
2x = 10
x = 5
2006-12-03 18:59:31
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answer #8
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answered by mad_integer 3
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7(x+7)=5x+59
7x+49=5x+59
7x-5x=59-49
2x=10
x=5
2006-12-04 16:13:59
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answer #9
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answered by arpita 5
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7(x+7)=5x+59
7x+49=5x+59
7x-5x=59-49
2x=10
x=5
2006-12-03 10:07:22
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answer #10
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answered by grrlgenius5173 2
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