Physics Question?

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Under standard conditions, the density of air is 1.293 kg/m3 and that of helium is 0.178 kg/m3. A spherical helium balloon lifts a basket plus cargo of mass 278.0 kg. What must be the minimum diameter of the spherical balloon?

2006-12-03 09:59:53 · 3 answers · asked by emmy 1 in Science & Mathematics ➔ Physics

3 answers

For equilibrium...density1 = density2
we're assuming infinite density for the cargo.
1.293 - 0.178 = 1.115
278 / 1.115 = 249.33 m^3
V = 4/3 π r^3
r = cube root (3V/4π) = 3.9 m

2006-12-03 10:07:11 · answer #1 · answered by feanor 7 · 0⤊ 0⤋

One subtraction and one division are all that is needed to solve this. You do the arithmetic.

2006-12-03 10:03:12 · answer #2 · answered by Anonymous · 0⤊ 1⤋

997 cm i think...

2006-12-03 10:02:28 · answer #3 · answered by michaeljoyzer 2 · 0⤊ 0⤋