What volume (mL) of 0.149 M NaOH contains 35.0 g of NaOH?

Answer 1

35 g of NaOH = 0.875 moles of NaOH
(40g of NaOH = 1 mole)

0.875 moles / 0.149 moles/L = 5.8725 L = 5872.5 mL

Answer 2

The molecular weight of NaOH is 40 (gram/mole). So the number of moles for 35.0 g of NaOH is 35.0/40=0.875 (mole).

Let v (L) be the volume of 0.149 M NaOH solution, which provides 0.875 mole of NaOH. We have

v x 0.149 =0.875

v=0.875/0.149=5.87 (L)

NOTE: You need to have the correct number of significant figures here.

5.87 L is 5870 mL (So 5870 mL is the final answer).

Answer 3

First, convert to moles from the given amount of grams using the molar masses of Na, O, and H from the periodic table.
35g NaOH x (1 mol/ 40 g) = .875 mol NaOH. Also, M = mol/L, so
.149 M NaOH = (.875 mol)/(x L), and x turns out to be 5.872 L. Lastly, convert to mL, and you have 5872.5 mL .

Answer 4

0.149 M NaOH

= 0.149 mol/L NaOH
= 0.000149 mol/mL NaOH
------------
mol NaOH * (22.9898g/mol Na + 15.9994g/mol O + 1.00794g/mol H)
=39.99714g/mol NaOH

0.000149 mol/mL NaOH * 39.99714g/mol NaOH
0.00595957 g/mL NaOH

Inverse it to get the units in the right order:

167.797 mL/g * NaOH * 35.0g NaOH
= 5872.9 mL
=5870 mL

Answer 5

Or try this equation
1 M -- 1000 ml -- 40 g NaOH
0.149 M -- X ml -- 35 g

X=(1*1000*35) / (0.149*40) = 5872.5 ml

Answer 6

If im information this precise you're able to get .0046024 kj basically in case you desire this: one thousand energy* = a million Calorie(food) /a million kilocalorie a million calorie = 4.184 Joules one thousand joules = a million kilojoule * the quantity of warmth required to strengthen a million g of water a million• Celsius is defined to be energy-decrease case.