Logarithms..?

Question

log3(5x+5) - log3(x2 - 1) = 0

log2(x - 2) + 5 = 8 - log2 4

please help.. Can you please show steps on how you solved it.. I want to see how I got my answers wrong.. Thanks

Answer 1

log3[(5x+5)/(x²-1)] = 0
(5x+5)/(x²-1) = 3^0 =1
5x+5 = x² - 1
0 = x² -5x -6
0 = (x - 6)(x + 1)

x = 6 (because -1 doesn't work in the original equation)

log2(x - 2) + 5 = 8 - log2 4 = 8 - 2 = 6
log2(x - 2) = 1
x - 2 = 2^1 = 2
x = 4

And don't think you're fooling anyone. If you really had answers you would have posted them.

If you just copy this down and turn it in, you learned nothing. That's your problem, not mine.

Answer 2

the log is the exponent ...
5x+5 / x^2 -1 = 1
5 (x+1) / (x+1)(x-1) = 1
5 / (x-1) = 1
x = 6


2^(x-2) * 2^5 = 2^8 / 2
2^(x+3) = 2^7
x = 4