Air resistance is proportional to your velocity. Thus more velocity means more air resistance.
2006-12-03 08:21:12
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answer #1
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answered by msi_cord 7
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If you double the speed of the car, it runs into twice as many air molecules per second, and hits each one twice as hard, so there is four times as much air resistance. Thus, the parasitic drag (that's what it is called) increases with the square of the velocity, so the power required increases as the cube of the velocity.
2006-12-03 08:39:11
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answer #2
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answered by Anonymous
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Air (or any fluid) resistance on a moving object is a force. Force is proportional to the rate of change of momentum (of the fluid, slowed down by hitting the object). If you do the maths you'll find the force is proportional to the square of the object's speed - approximately, depending on its shape.
Power = force x speed so the engine power needed to reach a certain speed is proportional to the cube of the speed (again, approximately). So, if a certain car has a top speed of 100mph, you'd need about eight times the engine power to reach 200 mph.
2006-12-03 08:27:44
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answer #3
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answered by DriverRob 4
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When a car is at a higher speed, the air has to accelerate more to reach the same velocity as the car. This higher acceleration results in a higher resistance (F or R = ma).
2006-12-03 10:27:43
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answer #4
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answered by Kemmy 6
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Because, the faster you propel something through air the more drag that it's going to cause as the air moves around the object.
2006-12-03 08:21:56
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answer #5
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answered by somewherein72 4
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Air resistance is caused by air molecules bashing into a solid object as it moves through the air, (or as the air moves relative to the solid object). If it moves faster, more air molecules will bash into it and they'll also hit it harder.
2006-12-03 20:13:53
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answer #6
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answered by chopchubes 4
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Because the car is cutting through the air faster and faster, it is creating higher and higher pressure in front of itself and the pressure causes air resistance
2006-12-03 08:22:08
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answer #7
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answered by exkingofspain 2
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see
http://en.wikipedia.org/wiki/Drag_coefficient
2006-12-03 08:19:58
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answer #8
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answered by ? 7
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