Factor/simplify:
sec^2x * tan^2x + sec^2x
I am not good at math AT ALL :[ Can anyone help me out?
2006-12-03 07:58:31 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Also:
csc^2x - 1 / cscx - 1
2006-12-03 08:19:07 · update #1
Since tan^2x+1=sec^2x then:
(sec^2x)(sec^2x-1)+sec^2x = (sec^2x)(tan^2x)+sec^2x
Simplifing to:
(sec(x))^4
2006-12-03 08:05:27 · answer #1 · answered by Shane W 1 · 0⤊ 0⤋
I am assuming sec^2x means sec(x)^2.
Pull out a sec(x)^2.
sec(x)^2 * (tan(x)^2 + 1) = sec(x)^2 * sec(x)^2 = sec(x)^4
2006-12-03 16:01:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
sec²x tan²x + sec²x
Factor out sec²x:
sec²x(tan²x + 1)
Use trig identity, sec² = tan² + 1
sec²x(sec²x) = (sec x)^4
2006-12-03 16:02:14 · answer #3 · answered by Jim Burnell 6 · 0⤊ 0⤋
it equals 123000
2006-12-03 16:00:56 · answer #4 · answered by Anonymous · 0⤊ 0⤋
ask your parents damn
2006-12-03 16:00:41 · answer #5 · answered by Anonymous · 0⤊ 1⤋