help me
2006-12-03 07:51:28 · 6 answers · asked by Walle 2 in Science & Mathematics ➔ Mathematics
I'm assuming these are systems of equations. I'll help with the first and the others will be similar.
x + 2y = 7
2x - 3y = -21
Multiply the first equation by -2 and add that to the second equation.
-2x - 4y = -14
2x - 3y = -21
-7y = -35
y = 5
Now substitute 5 in for y and solve for x.
x + 2(5) = 7
x+10 = 7
x = -3
Answer: (-3,5)
2006-12-05 09:52:28 · answer #1 · answered by MsMath 7 · 1⤊ 1⤋
69
2006-12-03 07:54:25 · answer #2 · answered by Anonymous · 1⤊ 0⤋
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2016-11-30 02:24:30 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Well there is no proposed question. "e" is a constant. You aren't asking anything you just gave a list of equations - all you can try to do is solve for y - but this is ridiculous. If you need help ask another question.
2006-12-03 08:00:24 · answer #4 · answered by ziggya1189 2 · 2⤊ 1⤋
If you are taking the class you should be able to do the work.♠
2006-12-06 17:31:29 · answer #5 · answered by # one 6 · 1⤊ 0⤋
y=(7-x)/2 y=... wait a min.. this is harder that i thought.. sorry
2006-12-03 07:57:10 · answer #6 · answered by ashley9_99 2 · 2⤊ 1⤋