Find the largest value of n for which 2^n will be a factor of 20.?

Answer 1

I think the answer would be 2 because that would be 4 and 2 and 4 are the only factors of 20 you could make with 2^n. For example:
2^1=2 2^2=4 2^3=8 2^4=16 2^5=32

Answer 2

one million. factor thoroughly: x^2 + 10x + 25 A) (x + 5)(x - 5) B) (x + 5)(x + 5) C) (x - 5)(x - 5) D) (x + 25)(x + one million) answer is B. x*x =x^2; 5*5=25; 5*x+5*x =10x 2. factor thoroughly: 3x^2 - 12 A) 3(x^2 - 4) B) 3(x + 2)(x + 2) C) 3(x + 2)(x - 2) D) (x + 2)(x - 2) answer is C. A is actual yet did not pass some distance sufficient. x^2-4 might stunning be factored to (x+4)(x-4). 3. factor thoroughly: 2x^2 - x - 10 A)(2x - 5)(x + 2) B) (2x + 5)(x - 2) C) (2x + 5)(x + 2) D) (2x - 5)(x - 2) answer is A. 2x*x =2x^2; (-5)(2)=-10;(-5)x +(2x)2 = -x 4. Simplify thoroughly: (4x -8) / (x-2) A) 4(x-2) / (x-2) B) 4 C) 8 D) 3x+4 answer is B. A did not cancel the x-2 words to get 4. it would that x won't have the skill to be such as 2 or you would be dividing by making use of 0 it rather is a no-no

Answer 3

20 = 2*10 = 2*2*5.
So there are only two factors of 2, so n = 2.