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If the solid has a molar mass of 208 g/mol after heating and a formula of XY, how many formula units of water are there in one?

Data:
mass before heating 27.650
mass after heating 25.610
mass of water 2.040

2006-12-03 07:09:51 · 4 answers · asked by disasterrrific 1 in Science & Mathematics Chemistry

4 answers

mole of water = 2.040 g / (18.02 g per mole) = 0.1132 mol H2O
mole of XY = 25.610 g / (208 g per mole) = 0.1231 mol XY

Based on these numbers, it seems to be 1 formula unit of H2O.

XY . 1H2O

2006-12-03 07:35:01 · answer #1 · answered by Math-Chem-Physics Teacher 3 · 0 0

If the mass of water is 2.040 for 208 g/mol - would you simply divide 2.040 by 208 ? Which would be .009808

But I'm not sure

2006-12-03 07:16:49 · answer #2 · answered by Dustin S 2 · 0 0

If the weightings are in grams, then:
2.040 grams of water is how many moles of water?
1 mole of water = 1 + 16 + 16
1 mole of H2O = 33 grams
2.040/33 = 0.062 moles of water

2006-12-03 07:17:40 · answer #3 · answered by Anonymous · 0 0

RMM of residue is 208
RMM of solid before heating is 208 x 27.650/25.610 = 225

As a result of heating the solid decomposes in the anhydrous solid and water therefore the same number of moles are present of residue and unheated solid. 27.650g of hydrated solid corresponds to 0.123 moles, therefore there is 0.123 moles of residue. 2.040g of water corresponds to 0.113moles of water which is approximately the same as the 0.123moles of the solid. this concludes that 1mole of solid decomposes to 1mole of residue and 1mole of water.

2006-12-03 07:39:53 · answer #4 · answered by trapshooting 1 · 0 0

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