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A centrifuge accelerates uniformly from rest to 15,000rpm in 220s. through how many revolutions did it turn in this time.

This ? is about constant angular acceleration; rolling

thanx for your help.

2006-12-03 06:49:05 · 2 answers · asked by willy o 1 in Science & Mathematics Physics

2 answers

θ = θ0 + ω0t + (1/2)αt^2
For uniform acceleration, α = ω/t
α = (15,000 rpm)(1 min/60 s)/(220 s)
α = (25 rev)/(22 s^2)
θ = 0 + 0 + (1/2)((25 rev)/(22 s^2))(220 s)^2
θ = 27,500 revolutions

2006-12-03 07:39:26 · answer #1 · answered by Helmut 7 · 1 2

15000rpm = 250rps. Uniform acceleration means that the average rps was 125, so in 220s, it revolved 125*220 = 27500times.

2006-12-03 07:02:45 · answer #2 · answered by JJ 7 · 1 0

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