2x^4-162
2006-12-03 06:33:15 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
2x^4-162
factor out a 2:
2(x^4 - 81)
the term in parenthesis is a difference between squares:
2[(x^2)^2 - 9^2]
or
2(x^2 + 9)(x^2 - 9)
again, the second term in parenthesis is a difference between squares:
2(x^2 + 9)(x^2 - 3^2)
or
2(x^2 + 9)(x + 3)(x - 3)
2006-12-03 06:35:50 · answer #1 · answered by Scott R 6 · 4⤊ 0⤋
2x^4-162 =
2(x^4-81) =
2(x² - 9)(x² + 9) =
2(x + 3)(x - 3)(x² + 9)
₢
2006-12-03 14:38:33 · answer #2 · answered by Luiz S 7 · 0⤊ 0⤋
2x^4-162 =
2x^4 = 162
x^4 = 162 : 2
x = ^4\/162
Factoring:
162| 2
..81| 3
..27| 3
....9| 3
....3|3
....1
162 = 2 x 3^4
x = 3 times root 4\/2
Ubderstand?
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2006-12-03 14:56:17 · answer #3 · answered by aeiou 7 · 0⤊ 3⤋
It must be equal to something otherwise, it is imcomplete. If I set it = to 0, then it becomes:
2x^4-162=0
2x^4=162
x^4=81
x=3
2006-12-03 14:39:36 · answer #4 · answered by Tony T 4 · 0⤊ 2⤋
2(x-3)(x+3)(x²+9)
2006-12-03 14:37:36 · answer #5 · answered by 7 · 0⤊ 0⤋