need help on math problem?

Question

this math problem is cazy can some one plzz help me on it?

y=2/3x {x is squared} - 4/5x
so if you can understand the problem it is Y equals two over 3 X squared minus 4 over 5 X

thanks for yur help

Answer 1

GIVEN:
y = [ 2/(3x²) ] - [ 4/(5x) ]

FIND:
The value(s) of "x".

LET:
y = 0 , to determine the root(s) of the function.

Let's start by SUBSTITUTING, using (PARENTHESIS), the value of "0" for "y".
___________________________

SOLUTION:
y = [ 2/(3x²) ] - [ 4/(5x) ]
(0) = [ 2/(3x²) ] - [ 4/(5x) ]
1(0) = [ 2/(3x²) ] - [ 4/(5x) ]
0 = [ 2/(3x²) ] - [ 4/(5x) ]

Now, SIMPLIFY the Right Hand Side of the equation by combining "like" terms.

First, we need a Greatest Common Factor to subtract the two fractions.
________________________________________

(0) = [ 2/(3x²) ] - [ 4/(5x) ]

GCF= 15x²

Multiply numerator and denominator by the SAME factor to get a denominator = 15x².
_____________________________________________

0 = { [(2)(5)] / [(3x²)(5)] } - { [(4)(3x)] / [(5x)(3x)] }
0 = [10/(15x²)] - [(12x)/(15x²)]

COMBINE "like" terms.
___________________________________

0 = [(10 - 12x)/(15x²)]

Factor out the GCF in the Numerator.
___________________________________________

0 = { [2(5 - 6x)] / (15x²) }
0 = [2/(15x²)] [(5 - 6x)/(15x²)]

Set each factor = 0, and SOLVE for "x" in the numerator.
______________________________________________

REMEMBER:
The denominator ≠0

Therefore, 15x² ≠0.

15x² ≠0
(15x²)/15 ≠0/15
x² ≠0
x² ≠0
√(x²) ≠±√(0)
x ≠±(0)
x ≠±1(0)
x ≠0
_____________________________

RESTRICTION on "x":
x ≠0
___________________________

Setting the numerator(s) = 0 and SOLVING for "x", we get:

[2/(15x²)] = 0 ; x ≠0
2 = 0
2 ≠0 Therefore, there is no x-intercept for this factor.

[(5 - 6x)/(15x²)] = 0 ; x ≠0
5 - 6x = 0
5 - 5 - 6x = 0 - 5
0 - 6x = -5
-6x = -5
-6x/(-6) = [ (- 5) ÷ (-1) ] / [ (-6) ÷ (-1) ]
x = [ (- 5) ÷ (-1) ] / [ (-6) ÷ (-1) ]

REDUCE for final answer! :o)
________________________________

FINAL ANSWER:
x = 5/6, where x ≠0

DOMAIN: all REAL numbers excluding zero. (- ∞, 0) U (0, ∞)

Good question! Contrats. on making to the end! ♥

Answer 2

x = 0.833333[...]x^2-1.25y

"x" equals eight and one-third tenths times x squared minus one and 1-quarter y.

X^2 and X aren't divisible in the same sequence. You need to isolate the variable the problem was already simplified as far is it could go when you gave it to us.

Ironduke, she said only one of the "X"s is squared.

Vivek would be right because its given in simplest form and there is no way to isolate the x and find y. without finding out y you can't find x. its already simplified.

Answer 3

ok the only way is to simplify which is x(2/3x-4/5) thats the only thing i can think of

Answer 4

y= 2/(3x^2) -4/(5x)=0
10/(15x^2) -12x/(15x^2) =0
(10-12x)/(15x^2)=0
10-12x = 0
-12x=-10
x = 5/6

Answer 5

the answer or its simpliest form is:

y= 2(5x-6)/15


how did i get it:

y= 2/3x (x^2/1) -4/5x
=2x^2/3x -4/5x
=10x^2 - 12x/ 15x ---> lcd
=2x(5x-6) / 15x ------> common monomial factor

y=2(5x-6) / 15

Answer 6

y= -2/15x squared

thats all i got.... its hard

Answer 7

You didn't specify what you're looking for.

Answer 8

wat do u actually want out of tis equation .

ya i got that y=2/3 x^2 - 4/5 x

but wat is to be done . wats the question