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4 answers

-3x-5 > 10

1) Add 5 to both sides.

-3x - 5 + 5 > 10
-3x > 15

2) Divide both sides by -3, remember that when you divide or multiply by a negative number in an inequality, the direction of the greater/less than sign switches.

x < - 5

2006-12-03 02:58:04 · answer #1 · answered by sft2hrdtco 4 · 1 0

Solving inequalities is the same as solving equations except whenever you multiply or divide by a negative number, you flip the sign.

I'd simply add five to each side, getting you -3x>15, then divide by -3. Since -3 is a negative number, you flip the sign of the inequality, meaning you end up with x<-5 rather than x>-5

2006-12-03 02:57:02 · answer #2 · answered by techwiz2000_2000 2 · 1 0

By _> I'm assuming you mean >= (greater than or equal to), so I'll write it like that to dispel confusion.

-3x - 5 >= 10

First, move the -5 to the right hand side to get +5

-3x >= 10 + 5
-3x >= 15

Now, divide both sides by -3. ***NOTE*** Every time you multiply or divide an inequality by a negative number, the sign shifts. In this case, the >= will switch to <=. Therefore,

x <= 5

2006-12-03 03:00:33 · answer #3 · answered by Puggy 7 · 0 0

Add 5 on both sides.
Divide both sides by -3.
-3x-5_>10
-3x>15
x>-5

2006-12-03 02:56:57 · answer #4 · answered by Nikko 2 · 0 1

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