Math Question.... solve with quadratic formula?

Question

Solve this equation using the quadratic formula...

2x^2+7x=-3

Answer 1

2x^2+7x=-3
2x^2+7x+3=0
x^2+(7/2)x+(3/2)=0

x1=-3
x2=-(1/2)

or

a=2, b=7, c=3

x1=(-b+sqrt((b^2)-4ac))/2a
=(-7+5)/4
=-(1/2)

x2=(-b-sqrt((b^2)-4ac))/2a
=(-7-5)/4
=-3

Answer 2

2x^2 + 7x = -3

becomes 2x^2 + 7x + 3 = 0 by adding +3 to both sides

using the quadratic formula
a = 2
b = 7
c = 3

Answer 3

a=2, b=7, c=3
Substitute the value in the quadratic formula.
x= -(1/2)
x= -3

Answer 4

get you equation in the form ax^2 + bx + c = 0
so 2x^2 +7x + 3 = 0

quadratic equation x = -b + or - sqr(b^2 -4ac)/2a

plugin variabls and solve for x twice

x= -7 + sqr(49 - 4(2)(3))/2(2)
x= -7 - sqr(49 - 4(2)(3))/2(2)

-4(3)(2) = -24, 2(2) = 4

x= -7 + sqr(49 - 24)/4
x= -7 - sqr(49 - 24)/4

49 - 24 = 25

x= -7 + sqr(25)/4
x= -7 - sqr(25)/4

sqr(25) = 5

x= -7 + 5/4
x= -7 - 5/4

5/4 = 1.25

x= -7 +1.25
x= -7 - 1.25

x = -5.75
x = -8.25

Answer 5

2x^2+7x=-3
2x^2+7x+3=0

It's hard to explain so please go to
http://www.purplemath.com/modules/quadform.htm

now, u can see the formula to get the value of x rite... x=-b........ if you plug that in the equation it becomes

x=-7 +or-squarerootof(7^2-4(2*3)) and all that divided by 2(2)

Answer 6

x= (-7(+ or -)sqrt(49-24))/4

x=(-7(+or-)5)/4

x= -12/4 , -2/4

x= -3,-1/2