I know that pressure is Force/Area but I have an investigation and am unsure what I should take to be my area.
Here is my method:
The equipment was set up corresponding to measurements already decided (e.g. how far away the hairdryer is away from the scales); one wooden boards was stuck on to the top of the weighing scales and the scales were reset to zero while another identical woodem board was – with clamps supporting it either side as to stop it dipping – parallel to the first but x cm above.
Air was then blown through the boards by an air source which is x cm’s away from them which produced a reading that I was able to turn in to Newton's.
However should I take the (imaginary) rectangle between the two boards as the measurements for area; or from the air source to the far side of the boards or something else?
I hope that this has made sense! Thanks again! -x-
2006-12-03 02:29:56 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Not sure I have fully understood where the boards are and what they are doing?
As far as I can understand from what you have said, the hair dryer is blowing onto the scales and it is the force of the air flow that creates pressure. The area you need is the physical area that the air flow is acting on. Isn't this the board that is resting on top of the scales ( I take it, this has been put on the scales metal pan? )
If this is the case, then the area will be that single boards width x length
2006-12-03 02:38:56 · answer #1 · answered by Stephen 3 · 0⤊ 0⤋
What you have is a Bernoulli's Principle Experiment where the column of air passing between the board produces lift on the lower board (and downforce on the upper board). The area involved would be the area of the board surface facing the air column, this area would be needed to calculate the air pressure difference created by the air column.
2006-12-03 10:55:10 · answer #2 · answered by a simple man 6 · 1⤊ 0⤋
The scales are measuring the force at the scales, and not at the source. The area should be the cross section of the flow at the scales, or the rectangle you described.
Way to go!
2006-12-03 10:35:03 · answer #3 · answered by maddojo 6 · 0⤊ 0⤋
If you are trying to prove Bernouilli's Theorem, then the area is that acting on by the differential air pressure. In this case it is the area of the lower board (plus any overlap from the scales).
How have you stopped air leaking in from the sides?
2006-12-03 15:45:27 · answer #4 · answered by waspy772004 3 · 0⤊ 0⤋
Hasn't this science all been done decades if not centuries ago? Wouldn't you want to read all about it before you set up your crude "woodem" boards and clamps and hairdryer?
You'd never get any kind of accurate information with that setup. What an exercise in futility. You're spinning your wheels in mud while trying to reinvent the wheel.
However, you are right about one thing, it's "something else".
2006-12-03 10:50:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋
sorry, no coffee yet
can't even understand it
2006-12-03 10:33:11 · answer #6 · answered by kurticus1024 7 · 0⤊ 0⤋
dude u r beat!!!!
2pts!! *****!!
whoops!!!
2006-12-03 10:31:26 · answer #7 · answered by Anonymous · 0⤊ 0⤋