x^2 d^2x/dy^2 + 2xdx/dy=0
How do you do this
2006-12-03 00:58:11 · 9 answers · asked by Glendon 1 in Education & Reference ➔ Homework Help
Well, x = 0 is certainly a solution.
So let's look for nonzero solutions.
Divide by x². Then x" = -2/x.
Integrate both sides to reduce it to a first order eqn.
x'= -2*log x + A,
where A is a constant.
That's as far as I got right now. I'll come back here later
and try to finish the job.
BTW here is a very useful website for differential equations.
http://tutorial.math.lamar.edu/AllBrowsers/3401/SecondOrder.asp
2006-12-03 07:49:12 · answer #1 · answered by steiner1745 7 · 0⤊ 0⤋
It's your homework,not mine and, anyway, I left school 46 years ago in 1960.
2006-12-03 01:03:12 · answer #2 · answered by dawleymouse 4 · 0⤊ 2⤋
the answers 0
it says so on the end after the =
2006-12-03 01:07:11 · answer #3 · answered by diveace1968 2 · 0⤊ 2⤋
Bloody hell, homework has got a lot harder since I was at school.
Sorry I haven't a clue.
2006-12-03 01:00:11 · answer #4 · answered by M1 5 · 1⤊ 2⤋
Sorry I don't remember, but I think it might be substitution...
2006-12-03 01:49:42 · answer #5 · answered by Anonymous · 0⤊ 1⤋
i don't know what ^ means, but what you sould do is find like terms, and im not reallt sure where you go from there.
2006-12-03 01:05:09 · answer #6 · answered by Alysse 2 · 0⤊ 2⤋
sorry, i tried but i got stuck...
2006-12-03 02:06:01 · answer #7 · answered by flying peanuts 3 · 0⤊ 0⤋
Why would you want to?
2006-12-03 01:00:29 · answer #8 · answered by stone 3 · 0⤊ 2⤋
I dont
2006-12-03 00:59:09 · answer #9 · answered by ? 5 · 0⤊ 2⤋