if a circular pool with a diameter of 23 feet is enclosed by a wooden deck that is 5 feet wide,?

Question

what is the area of the deck.im thinking you take the 23*5=115of area is this correct

Answer 1

The area of the pool is 415.476ft. (A= pi times 11.5^2)
you need a deck that will cover that area.
at 5ft wide, it would have to be 83.1ft in length. (415.476 divided by 5)

Answer 2

The larger circle, pool plus deck is 33 feet in diameter, radius 16.5 feet so 16.5 x 16.5 x 3.1416=855 sq.ft. now subtract the smaller circle (pool) from that 11.5 x 11.5 x 3.1416 =415 sq. ft. This leaves the deck at 440 square feet.

Answer 3

Here's the deal. You're dealing with two circles here----The pool , with an area = pi x ( 11.5 squared) and the circle encompassing both the pool and the deck with an area = pi x (16.5 squared)

[The 11.5 and 16.5 are the radii of the two circles respectively]

Subtract the area of the smaller from that of the larger-------------

[pi x (16.5 squared) - pi x (11.5 squared)] = area of the torus consisting of the deck.,

Answer 4

No, it is not 115.