Maths questions (Short)?

Question

CD's are packaged up in boxes of 84
Every 27 boxes are loaded onto 1 crate.

How many crates would be needed if you had 230000 CD's to pack?

How many boxes would be left over on the last crate?

How many CD's would be left in the last box?

Answer 1

mulitply 84 x 27 that will give you the cds per crate
divide that # into 230000..... the whole number is your full crates,,,,, the remainder is your paritial crate
take that remainder #, divide it by 27,,, the whole number is your full boxes on that last partial crate,, the remainder is the amount of cds in that last paritial box

Answer 2

1) no. of crates = no. of cd's/ number of boxes per cd/ number of boxes per crate = 230000/84/27 = 202.41 Since u cant have 1/2 a crate you need 101
2) 230000/84/27 - 101= amount of last crate filled
multiply this by 27 = 11.09 boxes
((230000/84/27 - 101)*27-11)*84 = number of cd's in remaining box = 8.000000004 or 8

Answer 3

1. The amount of crates needed :

The amount of CD's in each crates = 84*27 = 2268. The amount of crates needed = 230,000/2268 = 101.4109... (round it up to 102)

This means you'll need 102 crates, 101 of which will be filled full, and the 102th crate will only be partially filled.

2. The number of boxes in the last crate (102th):

The amount of CD's in the last crate = 230,000 - (101*84*27) = 932 CDs.
The amount of boxes needed = 932/84 = 11.0952.. (round it up to 12)

This means you'll need 12 boxes, 11 of them will be filled full, and the 12th will only be partially filled.

3. The number of CD in the last box = 932 - (11*84) = 8

Answer 4

mulitply 84 x 27 that will give you the cds per crate
divide that # into 230000..... the whole number is your full crates,,,,, the remainder is your paritial crate
take that remainder #, divide it by 27,,, the whole number is your full boxes on that last partial crate,, the remainder is the amount of cds in that last paritial box

Answer 5

230,000 CD's/85/box = 2,739 boxes (8 CD's in the last box)
2739 boxes/27 boxes/crate = 102 crates (12 boxes on the last crate)

Answer 6

5 x 3 is 15, the unfavourable makes it minus 15 (keep in ideas, effective situations effective or unfavourable situations unfavourable is efficacious, unfavourable and effective makes it unfavourable), plus 6 provides minus 9, which will change into the proper volume. Now for the bottom volume. 3 x 2 is 6, both negatives make it effective. a lot less 4 is two, plus 5 (the sq. root of 25) is 7. a lot less 4 -2 (2) x 3 that is 6 So, you've minus 9 divided with the aid of 6, which offer you with a unfavourable volume, of minus a million.5