A cleaning solutuion is made up of three chemicals: A, B, and C...there are equal amounts of A and B and four times as much C as there is A, what percentage of the bottle is filled with C?
2006-12-02 20:17:05 · 7 answers · asked by Antonio 2 in Science & Mathematics ➔ Mathematics
I got 66.67% when I substituted x for the amount of A and the amount of B, then used 4x as the amount of C. The total amount would be 6x, and 4/6= .666666 x 100 = 66.67%
2006-12-02 20:27:16 · answer #1 · answered by sweetienat123 6 · 0⤊ 0⤋
A= B, C=4A
Total bottle in terms of = A + A +4A = 6A
C = 4A
hence percentage is 4A/6A = 2/3 = 66.667% filled with C
2006-12-03 04:30:07 · answer #2 · answered by AMTV 3 · 0⤊ 0⤋
1 part A + 1 part B + 4 parts C
= 6 parts
hence, proportion of C= (4/6)*100 = 66.666%
2006-12-03 04:56:56 · answer #3 · answered by ? 3 · 0⤊ 0⤋
Let x = amount of solution A; this is also the amount of solution B. The amount of solution C is 4x. The total solution is then
x + x + 4x = 6x.
The percent of C is the (amount of C divided by the total) times 100:
4x/6x * 100
2006-12-03 04:29:10 · answer #4 · answered by gp4rts 7 · 0⤊ 0⤋
1A
1B
4C
4/6th of the bottle is filled with C
therefore 66.67% of the bottle is filled with C
2006-12-03 04:27:51 · answer #5 · answered by fwanc 2 · 0⤊ 0⤋
I dont kno but i think it is really easy :
4/6=2/3=%66.66
2006-12-03 04:26:29 · answer #6 · answered by HM H 2 · 0⤊ 0⤋
66.67%
2006-12-03 04:37:30 · answer #7 · answered by the brillant once! 2 · 0⤊ 0⤋