A picture on a page was reduced on a copier to 60% of its original size, and this copy was then reduced by 20%. What percent of the size of the original picture was the final copy?
A.12
B.20
C.40
D.48
E.52
answer: (( D ))
2006-12-02 20:11:30 · 6 answers · asked by rowie 1 in Science & Mathematics ➔ Mathematics
Okay, you figure at first it's .6 of its original size, and then they reduce it by 20%, which is to say, it is now .8 of its original size. Multiply .6 by .8, you get .48, or 48%.
2006-12-02 20:14:51 · answer #1 · answered by Answerer 2 · 0⤊ 0⤋
The Picture was reduce to 60% of its original size (X),
So its new size is Y=60*x/100, then we reduce 20% from Y, so we've got a new size Z, which equals the size of Y reduced by 20% of Y:
Z=Y-20*Y/100
Y=60*x/100
=>
Z=60*X/100-20*(60*x/100)/100
Z=60*x/100-12*X/100 =>
Z=48*X/100
so Z is 48% of X
2006-12-02 20:25:32 · answer #2 · answered by Ibraheem G 2 · 0⤊ 0⤋
Original picture is 100% = 100/100
It has been reduced to 60%
ie, 100% * 60% =60%
And once again this figure is reduced by 20%
ie. 60% - (60%*20%)= 60%-12% =48%
The original figure is 100%
Consequently, final copy is
100% * 48%= 48%
(please note the difference between the phrases reduced to and reduced by)
2006-12-02 22:03:21 · answer #3 · answered by shasti 3 · 0⤊ 0⤋
if you take 20% of 60 (60 x .20) you get 12.
then 60 - 12 = 48...
i don't know if that helps...?
2006-12-02 20:16:11 · answer #4 · answered by lyla 2 · 0⤊ 0⤋
Oh, come on, not ANOTHER of these simple homework questions?!
Use the PRINCIPLES explained in the (correct) answers to the last similar question that you posed just before this one.
2006-12-02 20:16:53 · answer #5 · answered by Dr Spock 6 · 0⤊ 1⤋
LET ORIGINAL SIZE =X
SIZE AFTER PROCESS 1 = .6X (SINCE REDUCED TO 60%)
SIZE AFTER PROCESS 2 = .6X - .2 * .6X= .48X (SINCE REDUCED BY 20% )
HENCE NOW THE SIZE = .48X = ANSWER D
2006-12-02 20:22:40 · answer #6 · answered by dj_devil 1 · 0⤊ 0⤋