0.1=(0.8)(0.84)^x
Steps:
1) Isolate the value raised to the "x" power by dividing both sides by (0.8) This will give you:
1/8 = (0.84)^x
2) Take the log or natural log of both sides, this will force the exponent value "x" to come down.
ln(1/8) = x*ln(0.84)
3) Isolate the variable "x" by dividing both sides by ln(0.84)
ln(1/8) / ln(0.84) = x
In decimal form, the answer is approximately equal to 11.9266
2006-12-02 18:02:03
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answer #1
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answered by sft2hrdtco 4
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divide both sides by 0.8 to get
0.1/0.8 = 0.8(o.84)^x /0.8
to give
1/8 = 0.84^x
mult both sides by 8
1 = 6.52^x
then take the log of both sides
log 1 = log 6.52^x
log1 = x log 6.52
then use a calculator to find x
hope this helps ok?
2006-12-03 04:00:25
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answer #2
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answered by Aslan 6
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0.1=(0.8)(0.84)^x
Interchanging two sides,
or, (0.8)(0.84)^x = 0.1
Dividing both sides by (0.8),
or, (0.84)^x = 0.1/0.8
or, (0.84)^x = 1/8
Taking log in both side,
or, Log{(0.84)^x} = Log(.125)
or, xLog(0.84) = Log(.125)
or, x = Log(.125) / Log(0.84)
or, x = 11.927 (Taking 3 decimal)
The solution is x = 11.927
2006-12-03 03:30:05
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answer #3
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answered by JShahreer 1
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log 0.1 divide by log((0.8)(0.84)) = x
2006-12-03 01:58:43
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answer #4
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answered by prashmanic 4
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0.1=(0.8)(0.84)^x divide by .8
.125=.84^x take ln of each side
x ln .84=ln .125 divide by ln .84
x=ln .125/ ln .84=11.9
2006-12-03 02:03:46
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answer #5
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answered by yupchagee 7
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Rewriting:
(0.84)^x = 1/0.8 = 1.25
Take log(base 10) = log10() both sides
log10[0.84^x] = log10[1.25]
log10[0.84^x] = xlog10[0.84] = log10[1.25]
Solving for x:
x = log10[1.25]/log10[0.84]
2006-12-03 02:01:50
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answer #6
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answered by kellenraid 6
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0.1=(0.8)(0.84)^x
> (0.1)/(0.8) =(0.84)^x
> 0.125 = (0.84)^x
> log (0.125) = log (0.84)^x
> log (0.125) = x log (0.84)
> x = {log (0.125)} / {log (0.84)}
> x = 11.927
2006-12-03 02:06:47
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answer #7
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answered by Sakib 1
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