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0.1=(0.8)(0.84)^x



* can you show me step by step please =]?

2006-12-02 17:53:32 · 7 answers · asked by blah 3 in Science & Mathematics Mathematics

7 answers

0.1=(0.8)(0.84)^x

Steps:
1) Isolate the value raised to the "x" power by dividing both sides by (0.8) This will give you:
1/8 = (0.84)^x

2) Take the log or natural log of both sides, this will force the exponent value "x" to come down.
ln(1/8) = x*ln(0.84)

3) Isolate the variable "x" by dividing both sides by ln(0.84)
ln(1/8) / ln(0.84) = x

In decimal form, the answer is approximately equal to 11.9266

2006-12-02 18:02:03 · answer #1 · answered by sft2hrdtco 4 · 0 0

divide both sides by 0.8 to get

0.1/0.8 = 0.8(o.84)^x /0.8

to give

1/8 = 0.84^x

mult both sides by 8

1 = 6.52^x

then take the log of both sides

log 1 = log 6.52^x

log1 = x log 6.52

then use a calculator to find x

hope this helps ok?

2006-12-03 04:00:25 · answer #2 · answered by Aslan 6 · 0 0

0.1=(0.8)(0.84)^x

Interchanging two sides,

or, (0.8)(0.84)^x = 0.1

Dividing both sides by (0.8),

or, (0.84)^x = 0.1/0.8
or, (0.84)^x = 1/8

Taking log in both side,

or, Log{(0.84)^x} = Log(.125)
or, xLog(0.84) = Log(.125)
or, x = Log(.125) / Log(0.84)
or, x = 11.927 (Taking 3 decimal)
The solution is x = 11.927

2006-12-03 03:30:05 · answer #3 · answered by JShahreer 1 · 0 0

log 0.1 divide by log((0.8)(0.84)) = x

2006-12-03 01:58:43 · answer #4 · answered by prashmanic 4 · 0 0

0.1=(0.8)(0.84)^x divide by .8
.125=.84^x take ln of each side
x ln .84=ln .125 divide by ln .84
x=ln .125/ ln .84=11.9

2006-12-03 02:03:46 · answer #5 · answered by yupchagee 7 · 0 0

Rewriting:
(0.84)^x = 1/0.8 = 1.25
Take log(base 10) = log10() both sides
log10[0.84^x] = log10[1.25]
log10[0.84^x] = xlog10[0.84] = log10[1.25]
Solving for x:
x = log10[1.25]/log10[0.84]

2006-12-03 02:01:50 · answer #6 · answered by kellenraid 6 · 0 0

0.1=(0.8)(0.84)^x
> (0.1)/(0.8) =(0.84)^x
> 0.125 = (0.84)^x
> log (0.125) = log (0.84)^x
> log (0.125) = x log (0.84)
> x = {log (0.125)} / {log (0.84)}
> x = 11.927

2006-12-03 02:06:47 · answer #7 · answered by Sakib 1 · 0 0

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