GIVEN:
2x ( x - 5 ) = 0
FIND:
The value(s) for "x".
Start, by setting each factor = 0 and SOLVING for "x".
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SOLUTION:
2x ( x - 5 ) = 0
2x = 0
2x / 2 = 0 / 2
x = 0
x - 5 = 0
x - 5 + 5 = 0 + 5
x + 0 = 5
x = 5
CHECK using the values for "x" by SUBSTITUTING using (parenthesis) into the GIVEN equation.
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CHECK#1:
Let x = 0
2x ( x - 5 ) = 0
2(0) [ (0) - 5 ] = 0
2(0) [ 1(0) - 5 ] = 0
0 ( 1 - 5 ) = 0
0 ( - 4 ) = 0
0 = 0 ...The statement is TRUE. Therefore, x = 0 is a solution.
CHECK#2:
Let x = 5
2x ( x - 5 ) = 0
2(5) [ (5) - 5 ] = 0
2(5) [ 1(5) - 5 ] = 0
10 ( 5 - 5 ) = 0
10 ( 0 ) = 0
0 = 0 ...The statement is TRUE. Therefore, x = 5 is a solution, too.
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FINAL ANSWER:
x = 0 and 5
Congrats. on making it to the end! ♥
2006-12-02 16:19:10
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answer #1
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answered by LovesMath 3
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x=0
2006-12-02 23:51:31
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answer #2
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answered by BaBy PopN' 2
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2x(x - 5) = 0
2x = 0 OR x - 5 = 0
therfore x = 0 or 5
2006-12-02 23:52:17
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answer #3
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answered by arumisan 2
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in this cace 2x= 0 or (x-5)= 0 ,so x=0 or x=5
2006-12-03 00:07:02
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answer #4
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answered by Anonymous
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Are you trying to find the numbers for x for which it equals zero? If so then x = 0 or x = 5.
2006-12-02 23:51:03
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answer #5
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answered by immageek 1
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2x(x - 5) = 0
So 2x = 0 or x - 5 = 0
ie x = 0 or 5
2006-12-02 23:48:08
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answer #6
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answered by Wal C 6
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One answer is X=5; here is how
2x(x-5)=0
Divid each side by 2x
x-5 = 0 /* Dividing 0 by anthing is 0 */
x=5
2006-12-02 23:49:51
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answer #7
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answered by A Stranger 3
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2x(x-5)=0
2x^2-10x=0
lets simplfy it by dividing both sides with 2
x^2-5x=10
and there are two value for x
x=5 x=0
2006-12-03 06:08:01
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answer #8
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answered by Anonymous
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EITHER 2X OR X-5 HAS TO BE 0 FOR 2X(X-5)=0
SOLVE FOR EACH
2X=0 AND
X-5 =0
YOU GET X=(0,5)
2006-12-02 23:57:08
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answer #9
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answered by blueseaspider 1
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either 2x=0 or x=0
x-5=0 or x=5
so solution set{0,5}
2006-12-02 23:49:34
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answer #10
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answered by raj 7
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