Find the equation of the line that is perpendicular to 2x + y=4 and passes through the point (-2,-1).?

Question

(Answer= 1/2x) Please show your work. Thank you!

Answer 1

Change to slope-intercept
y=-2x+4
Slope=-2
Slope of the normal(perpendicular) line is the negative reciprocal
Slope of the normal=1/2
Use standard form y-y1=m(x-x1) with the given point and slope
y+1=(1/2)(x+1)
Change to slope-intercept form
y=1/2x+1-1
y=1/2x

Answer 2

Find the equation of the line that is perpendicular to 2x + y = 4 and passes through the point (-2,-1).?

The line perpendiculat to 2x + y = 4 (slope = -2) is of the form

x - 2y = c (slope = 1/2 and 1/2 * -2 = -1)

When x = -2 y = -1
So -2 - -2 = c
ie c = 0

So the required line is x - 2y = 0

Answer 3

situation: 2x+y=4 (-2,-a million) even as searching Perpendicular strains you would possibly want to keep in mind that Perpendicular is the option and reciprocal of the unique slope. Step a million: placed equation in y=mx+b variety: 2x+y=4 : Equation -2x -2x : Subtract y= -2x+4 : Simplify you want to save in ideas this formulation: y=mx+b m is the slope and b is the y intercept step 2: ok now that you've the equation in impressive variety you want to apply the point slope variety to locate the perpendicular line. formulation: y-y1=m (x-x1) y-y1=x-x1 : formulation y-(-a million) = 2 (x-(-2)) : replace numbers into equation y+a million = 2(x+2) : Simplify y+a million = 2x+4 : Subtract -a million -a million y = 2x-3 : answer Watch your negative signs and indicators!!!!! Step 3: okay now that you acquire your equation you want to locate the slope it really is: 2x Now you want to make it the option signal. so it will be -2x. ultimately you want to locate the reciprocal which may be: -a million/2x Step 4: PLUG all of it mutually: y= -a million/2x-3 is your very last answer! wish this Helped!!

Answer 4

first, put the original equation in y=mx+b form.
y=-2x+4
perpendicular equations have negative recipricals. (3 and-1/3, -5/7 and 7/5)
so the equation that you're going to be dealing with will have a slope that's a negative reciprical of -2x (x/2)
the whole equation will then be
y=x/2+b
to find a "b" for the equation, plug in the point
-1=-2/2+b
b=-1+2/2
b=0
so the equation that is perpendicular to the equation 2x=y=4 and runs through the point (-2,-1) is y=x/2

Answer 5

2x + y = 4
y = -2x + 4

m (slope) = -2

For lines to be perpendicular, the product of their slopes must be -1.

-2m* = -1 (where m* is the slope of the perpendicular line)
m* = 1/2

The perpendicular line has the form:

y = (1/2)x + b (where b is the y-intercept)

If the perpendicular line passes through (-2, -1), then:

y = (1/2)x + b
-1 = (1/2)(-2) + b
-1 = -1 + b
0 = b

y = (1/2)x + 0
y = (1/2)x -- this is the equation of the perpendicular line you're seeking.

Answer 6

Change to Y=mx+b

2x + y = 4
y = -2x + 4

Slope is one half

Plug numbers in to find b

-1 = -2(1/2) + b
-1 = -1 + b
add one to both sides
0 = b
Plug back into y=mx+b

Y = 1/2x + 0 (don't need the zero)

Answer 7

2x+y=4
y=-2x+4
slope is -2
slope of perpinducular is 1/2
y=x/2+b
-1=-2/2+b
-1=-1+b
b=0
y=x/2