Given triangle ABC with A=62 degrees; B=51 degrees and c=19, find the side a?

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2006-12-02 15:18:22 · 3 answers · asked by hans d 1 in Education & Reference ➔ Homework Help

If A = 62 and B = 51, C must = 67.
Law of Sines: a / (sinA) = b / (sinB) = c / (sinC)
a / (sin62) = (19) / (sin67)
a = 18.2

2006-12-02 15:26:08 · answer #1 · answered by Cynyeh 3 · 0⤊ 0⤋

The angles must add up to 180, so use A and B to find C. Then use the sine rule (it's in your math book.)

2006-12-02 15:27:02 · answer #2 · answered by banjuja58 4 · 0⤊ 0⤋

Not enough information to solve.

2006-12-02 15:25:54 · answer #3 · answered by Poncho Rio 4 · 0⤊ 0⤋