alright, I am trying to factor and simplify this expression: 81x^2-144y^2
-this would be difference of two squares
-A^2-B^2=(A+B)(A-B)
** i got, (9x+12y)(9x-12y)
- should I factor it further than this or am I done???
2006-12-02 12:56:53 · 9 answers · asked by im_a_goofy_chick 2 in Science & Mathematics ➔ Mathematics
next factor : 3(3x+4y) 3(3x-4y)=6 (3x-4y)????
2006-12-02 13:00:34 · update #1
81x²-144y² =
(9x + 12y)(9x - 12y) =
9(3x + 4y)(3x - 4y)
₢
2006-12-02 13:03:01 · answer #1 · answered by Luiz S 7 · 0⤊ 0⤋
one million. 15 - x over 4 = -8 (15 - x) / 4 = -8 (15 - x) = -32 -(15 - x) = 32 x = 40 seven 2. what happens if the 8 have been an excellent? 15 - x over 4 = 8? (15 - x) / 4 = 8 15 - x = 32 x = 15 -32 = -17 3. additionally dealing with percents! what could the % improve be? $50.00 is the unique cost $eighty.00 is the hot cost % improve = 60 4. discover the low cost cost 40 9.ninety 9 low cost 25% 37.40 9
2016-12-13 18:54:09 · answer #2 · answered by keira 4 · 0⤊ 0⤋
Yes, you should factorize till it cannot be done further. The last step in your answer would be 3*(3x+4y)*3*(3x-4y) which would be 9*(3x+4y)(3x-4y)
2006-12-02 13:18:34 · answer #3 · answered by greenhorn 7 · 0⤊ 0⤋
If the question is to factor, then you should factor completely, so you would have to factor out a 3 from each binomial.
2006-12-02 12:59:16 · answer #4 · answered by Anonymous · 0⤊ 0⤋
You should keep going. A three can be factored from each linear factor.
Then you'll be done.
2006-12-02 12:59:16 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Keep going - there is one more factor you can draw out of there. :-)
OK - I was trying to do it without telling you the answer, but to check yourself, the additional factor is "9".
2006-12-02 12:58:49 · answer #6 · answered by sep_n 3 · 0⤊ 0⤋
YES U DO , TAKE COMMON FACTOR 9
2006-12-02 12:59:35 · answer #7 · answered by Anonymous · 0⤊ 0⤋
I have been trying to figure that one out myself for some time.
2006-12-02 13:04:26 · answer #8 · answered by Anonymous · 0⤊ 0⤋
yes
3(3x+4y)(3)(3x-4y)
9(3x+4y)(3x-4y)
actually you should have started as
9(9x^2-16y^2)
9(3x+4y)(3x-4y)
2006-12-02 13:00:21 · answer #9 · answered by raj 7 · 0⤊ 0⤋