1. 2y"2+5y+2
2. 4m"2-13m+3
2006-12-02 12:46:36 · 4 answers · asked by guyana_bhai_2003 1 in Science & Mathematics ➔ Mathematics
1.(2y+1)(y+2)
2.(4m-1)(m-3)
2006-12-02 12:51:03 · answer #1 · answered by raj 7 · 1⤊ 0⤋
1. 2y^2 + 5y + 2
= 2y^2 + 4y + y + 2 (2 * 2 = 4 = 4 *1 and 4 + 1 = 5)
= 2y(y + 2) + 1(y + 2)
= (2y + 1)(y + 2)
2. 4m^2 - 13m + 3
= 4m^2 - 12m - m + 3 (4 * 3 = 12 = -12 * -1 and -12 + -1 = -13)
= 4m(m - 3) -1(m - 3)
= (4m - 1)(m - 3)
2006-12-02 20:55:24 · answer #2 · answered by Wal C 6 · 0⤊ 0⤋
1. 2y"2+5y+2=2y"2+4y+y+2=2y*(y+2)+1*(y+1)
=(y+2)*(2y+1)
2. 4m"2-13m+3=4m"2-12m-m+3
=4m*(m-3)-1*(m-3)
= (4m-1)*(m-3)
2006-12-02 21:07:39 · answer #3 · answered by greenhorn 7 · 0⤊ 0⤋
1.)
2y^2 + 5y + 2
y = (-b ± sqrt(b^2 - 4ac))/(2a)
y = (-5 ± sqrt(5^2 - 4(2)(2)))/(2(2))
y = (-5 ± sqrt(25 - 16))/4
y = (-5 ± sqrt(9))/4
y = (-5 ± 3)/4
y = (-8/4) or (-2/4)
ANS : (2y + 1)(y + 2)
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2.)
4m^2 - 13m + 3
m = (-(-13) ± sqrt((-13)^2 - 4(4)(3)))/(2(4))
m = (13 ± sqrt(169 - 48))/8
m = (13 ± sqrt(121))/8
m = (13 ± 11)/8
m = (2/8) or (24/8)
ANS : (4x - 1)(x - 3)
2006-12-02 21:14:43 · answer #4 · answered by Sherman81 6 · 0⤊ 0⤋